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Re: speed distance & time



In article <39213A39.30EE6619@ozemail.com.au>,
  Anita Lukaszyk <neety@ozemail.com.au> wrote:
> This reminds me of first year Physics. Stop it now!!!   :)
I have to live with it for the rest of my life:-)



> Hubert Lam wrote:
>
> > v = s/t
> >
> > where v is velocity (or speed if you don't care about direction)
> > s is displacement (or distance if you don't care about direction)
> > and t is time.
> >
> > from this you can derive the following:
> >
> > v = u + at
> >
> > where a is the acceleration of the object
> > v is the final velocity
> > and u is the initial velocity
> >
> > and hence you have
> >
> > v^2 = u^2 + 2as
> >
> > and s = ut + 0.5a(t^2)
> >
> > All you need to know is three of the variables and find the
relevant equation of motion and plug
> > (substitute) the numbers into the correct places.

And these are the ideal case, acceleration is not constant all the time
therefore you need to throw in intergrationzzzzzzzzzzzzzzzzzzzzzzz......

--
Cheers

James


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